- 题解
买铅笔
- @ 2023-8-9 10:19:04
#include #include #include using namespace std; int main(){ int a1,a2,b1,b2,c1,c2,n,s1=0,s2=0,s3=0; cin>>n>>a1>>a2>>b1>>b2>>c1>>c2; if(n%a10){ s1=n/a1*a2; }else{ s1=(n/a1+1)*a2; } if(n%b10){ s2=n/b1*b2; }else{ s2=(n/b1+1)b2; } if(n%c1==0){ s3=n/c1c2; }else{ s3=(n/c1+1)*c2; } if(s1>s2){ if(s2>s3){ cout<<s3<<endl; }else{ cout<<s2<<endl; } }else{ if(s1>s3){ cout<<s3<<endl; }else{ cout<<s1<<endl; } } return 0; }
1 条评论
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董的都懂 @ 2023-8-9 10:20:02666
- 1